contestada

A girl playing tug-of-war with her dog pulls the dog a distance of 8.0m by exerting a force at an angle of 18° with the horizontal. If the amount of work the girl does in pulling the dog is 190 J, what is the magnitude of the force?

Respuesta :

Answer:

25 N

Explanation:

Work is a product of force and perpendicular distance moved.

W=Fd where F is force exerted and d is perpendicular distance.

However, for this case, the distance is inclined hence resolving it to perpendicular so that it be along x-axis we have distance as [tex]dcos\theta[/tex]

Therefore, [tex]W=Fdcos\theta[/tex]

Making F the subject of the formula then

[tex]F=\frac {W}{dcos\theta}[/tex] where [tex]\theta[/tex] is the angle of inclination. Substituting 190 J for W then 18 degrees for [tex]\theta[/tex] and 8 m for d then

[tex]F=\frac {190}{8cos18^{\circ}}\approx 25N[/tex]