Answer:
300 m
Explanation:
For an object travelling with uniform motion (=constant velocity), the distance covered by the object is given by the equation:
[tex]d=vt[/tex]
where
d is the distance covered
v is the speed of the object
t is the time elapsed
In this problem we have:
- For Car A,
v = 20 m/s (speed)
t = 30 s
So the distance covered by car A is
[tex]d_A=vt=(20)(30)=600 m[/tex]
- For car B,
v = 30 m/s
t = 30 s
So the distance covered by car B is
[tex]d_B=vt=(30)(30)=900 m[/tex]
So during this time, the additional distance covered by car B is
[tex]d_B-d_A=900-600=300 m[/tex]