Answer:
A
Step-by-step explanation:
Given
x² + 6x + 4 = 0 ( subtract 4 from both sides )
x² + 6x = - 4
Solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = - 4 + 9, that is
(x + 3)² = 5 ( take the square root of both sides )
x + 3 = ± [tex]\sqrt{5}[/tex] ( subtract 3 from both sides )
x = - 3 ± [tex]\sqrt{5}[/tex] , thus
x = - 3 - [tex]\sqrt{5}[/tex] → A
x = - 3 + [tex]\sqrt{5}[/tex]
