Immediately after the switch is closed, determine the value of the charge Qon the capacitor, the voltage Von the capacitor. Also, find the current ithrough the 20-â„¦ resistor (R3) that is in parallel with the capacitor. Make sure you clearly explain your reasoning.

Immediately after the switch is closed the capacitor, which was initially discharged, has had not enough time to collect any charge; therefore, the charge on the capacitor is zero.

Also, since there is no charge on the capacitor, there is no potential difference (voltage) across the capacitor immediately after the switch is closed.

Going around the circuit gives

[tex](1). \: \: V- IR_1-I_2R_3-IR_2 =0,[/tex]

where [tex]I[/tex] is the current through resistors [tex]R_1[/tex], [tex]R_2[/tex], and [tex]I_3[/tex] is the current through [tex]R_3[/tex].

Now since there is no potential across the capacitor, the current is not divided at the junction; therefore, [tex]I_2 =I[/tex], which gives

[tex](1). \: \: V- IR_1-IR_3-IR_2 =0,[/tex]

[tex]I = \dfrac{V}{R_1+R_2+R_3}[/tex]

[tex]I = \dfrac{120V}{20\Omega+20\Omega+20\Omega }[/tex]

[tex]\boxed{I =2A}[/tex]

which is the current through [tex]R_3[/tex] immediately after the switch is closed.

adefioyelaoye adefioyelaoye · Answer 2 · 2022-03-18T17:19:22+01:00

2A is the current through R₃ immediately after the switch is closed.

What is Current?

This is defined as a stream of charged particles, such as electrons moving through an electrical conductor or space.

Immediately after the switch is closed the charge on capacitor and potential difference is zero.

Going around the circuit gives V - IR₁ - I₂R₃ - IR₂ = 0

where is the current through resistors R₁ ,R₂ , and I₃ is the current through R₃.

We were told that potential is absence which means V - IR₁ - IR₃ - IR₂ = 0

I = V/ R₁ + R₂ + R₃

I = 20V / 20Ω + 20Ω + 20Ω

I = 2A.

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