J'(2,2) , K'(6,2), L'(6,4) and M'(2,4)
Explanation:
Given:
The coordinates of the rectangle are:
J(3, 3), K(9, 3), L(9, 6), and M(3, 6)
The scale factor is 2/3
New coordinates = ?
Multiplying the coordinates by 2/3 to find the vertices of the image
[tex]J(3, 3) = J' (\frac{2}{3} . 3 , \frac{2}{3} . 3) = J' (2,2)\\\\K(9, 3) = K' (\frac{2}{3} . 9 , \frac{2}{3} . 3) = K' (6,2)\\\\L(9, 6) = L' (\frac{2}{3} . 9 , \frac{2}{3} . 6) = L' (6,4)\\\\M(3, 6) = M'(\frac{2}{3} . 3 , \frac{2}{3} . 6) = M' (2,4)[/tex]
The vertices of the image are:
J'(2,2) , K'(6,2), L'(6,4) and M'(2,4)
