Answer:
Volume of the cone =[tex]120.99inch^2[/tex]
Step-by-step explanation:
Circumference of the base=16.3 inch
[tex]16.3= 2\pi r[/tex]
As, [tex]\pi =\frac{22}{7} =3.14[/tex]
[tex]16.3=2*3.14*r\\\\16.3=6.28*r\\\\r=16.3/6.28\\\\r=2.60 inch[/tex]
Volume of the right circular cone
[tex]=\pi *r^2*\frac{h}{3}[/tex]
Volume [tex]=3.14*(2.60*2.60)*\frac{17.1}{3} \\\\=3.14*6.76*5.7\\\\=3.14*38.53\\\\=120.99inch^3[/tex]
