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Answer: 306 grams are there in 2.50 moles of potassium chlorate

Explanation

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

given mass of potassium chlorate = ?

Molar mass of potassium chlorate = 122.55 g/mol

Putting in the values we get:

[tex]2.50=\frac{xg}{122.55g/mol}[/tex]

[tex]x=2.50mol\times 122.55g/mol=306g[/tex]

306 grams are there in 2.50 moles of potassium chlorate

The mass of Potassium chlorate is 306.25 grams.

Number of Moles:

It is defined as the ration of given mass over molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given:

Number of moles = 2.50 moles

Molar mass of Potassium chlorate = 122.5 g/mol

To find:

Mass of Potassium chlorate=?

On substituting the values in the above formula:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\\text{Given mass}= \text{Number of moles}* \text{Molar mass}\\\\\text{Given mass}= 2.50*122.5\\\\\text{Given mass}=306.25g[/tex]

Thus, the mass of Potassium chlorate is 306.25 grams.

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