Answer:
45 J
Explanation:
Assuming the level at which the ball is thrown upwards is the ground level,
We can use the equations of motion to obtain the maximum height covered by the ball and then calculate the potential energy
u = initial velocity of the ball = 3 m/s
h = y = vertical distance covered by the ball = ?
v = final velocity of the ball at the maximum height = 0 m/s
g = acceleration due to gravity = -9.8 m/s²
v² = u² + 2ay
0 = 3² + 2(-9.8)(y)
19.6y = 9
y = (9/19.6)
y = 0.459 m
The potential energy the ball will have at the top of its motion = mgh
mgh = (10)(9.8)(0.459) = 45 J
Hope this Helps!!!
According to the question,
We know the relation,
→ [tex]v^2=u^2+2ay[/tex]
By putting the values, we get
[tex]0 = 3^2+2(-9.8) (y)[/tex]
[tex]19.6 y =9[/tex]
[tex]y = \frac{9}{19.6}[/tex]
[tex]= 0.459 \ m[/tex]
hence,
The potential energy,
= [tex]mgh[/tex]
= [tex]10\times 9.8\times 0.459[/tex]
= [tex]45 \ J[/tex]
Thus the above response is right.
Learn more about potential energy here:
https://brainly.com/question/964838
