Answer:
NH4+and −OH
Explanation:
The reaction of the ammonia and water is as follows:
NH₃ + H₂O = NH₄⁺ + OH⁻
The reaction is an equilibrium reaction. The NH₃ is a Lewis base. It accepts a proton. The H₂O is a Lewis acid, it donates a proton to the NH₃
Thus, the reaction above is correct.
Answer:
NH₄⁺ and OH⁻
Explanation:
The reaction of NH₃ and H₂O can be as follows:
NH₃ + H₂O --------> NH₂⁻ + H₃O⁺
NH₃ + H₂O --------> NH₄⁺ + OH⁻
Now which of these 2 equations is the correct one?
Well, we need to analyze the compouds per separate.
The case of NH₃, Nitrogen has 5 electrons, and we can see that 3 of them are bonding with the hydrogens. So it has 2 lone pairs available for any reaction. Same thing happen with the water. it has 4 lone pairs available for any reactions.
However, the lone pair of the nitrogen are more available because it have less electronegativy than oxygen, therefore, the NH₃ will act as a base in the reaction, while the water will act as acid.
If this s the case, NH3 is a base so it will donate an atom of hydrogen to the water, and the water as acid, will accept that. (Acid base theory by Bronsted - Lowry), therefore the correct reaction will be:
