Answer:
Answer is imaginary roots
Step-by-step explanation:
[tex] ({4x}^{3} - {5x}^{2} + 3x) + ( - {2x}^{3} - {x}^{2} + 6x) \\ 2 {x}^{3} - 6 {x}^{2} + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^{2} - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^{2} - 3x + \frac{9}{2} = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^{2} - 3x = - \frac{9}{2} \\ adding \: \frac{1}{2} \times (coefficient \: of \: x) \: whole \: square \\ [/tex]
On solving the above mentioned equation we get some imaginary values.
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