Respuesta :
Answer:
Volume of the cone= [tex]425.07feet^3[/tex]
Step-by-step explanation:
Volume of a right circular cone:
[tex]\frac{1}{3} *\pi *r^2*h[/tex]
For, height(h)= 4.5 feet
Diameter= 19 feet
Radius(r)= 19/2= 9.5 feet
As, [tex]\pi =\frac{22}{7}=3.14[/tex]
Volume of the cone :
[tex]=\frac{1}{3} *3.14*(9.5*9.5)*4.5\\\\=\frac{1}{3}*3.14* 90.25*4.5\\\\=\frac{1}{3} *3.14*406.125\\\\=\frac{1275.23}{3}\\\\ =425.07feet^3[/tex]
The volume of the cone with given dimensions is [tex]425.07feet^3[/tex]
Answer:
425.3 ft
Step-by-step explanation:
\text{Volume of Cone:}
Volume of Cone:
V=\frac{1}{3}\pi r^2h
V=
3
1
πr
2
h
\text{Find radius:}
Find radius:
r=\frac{\text{diameter}}{2}=\frac{19}{2}=9.5
r=
2
diameter
=
2
19
=9.5
h=4.5\hspace{40px}r=9.5
h=4.5r=9.5
Needed information
V=
V=
\,\,\frac{1}{3}\pi r^2h
3
1
πr
2
h
V=
V=
\,\,\frac{1}{3}\pi (9.5)^2(4.5)
3
1
π(9.5)
2
(4.5)
Plug in
V=
V=
\,\,425.29310548
425.29310548
Evaluate in calculator
V\approx
V≈
\,\,425.3\text{ ft}^3
425.3 ft
3
Round to the nearest tenth
