Respuesta :
Answer: It is a more efficient way to find x2k than by multiplying x by itself the appropriate number of times.
Step-by-step explanation: Please find the attached file for the solution

The use of
[tex] { {x}^{2} }^{k} [/tex]
is a more efficient way to multiplying than starting with x and successively squaring
Given:
real number = x
positive integer = k
[tex] { {x}^{2} }^{k} [/tex]
Starting with x and squaring to find x², x⁴, xⁿ
The efficient way of multiplying is
[tex] { {x}^{2} }^{k} [/tex]
where, k = 1, 2, 3, 4,.....…
check:
when k = 1
[tex] { {x}^{2} }^{1} [/tex]
= x²
when k = 2
[tex] { {x}^{2} }^{2} [/tex]
= x⁴
when k = 3
[tex] { {x}^{2} }^{3} [/tex]
=
[tex] { {x}^{2 \times 2 \times 2} } [/tex]
=
[tex] {x}^{8} [/tex]
Therefore,
[tex] { {x}^{2} }^{k} [/tex]
is a more efficient way to multiplying.
Learn more about exponent:
https://brainly.com/question/11464095