Given a real number x and a positive integer k, determine the number of multiplications used to find x2k starting with x and successively squaring (to find x2, x4, and so on). Is this a more efficient way to find x2k than by multiplying x by itself the appropriate number of times?

Respuesta :

Answer: It is a more efficient way to find x2k than by multiplying x by itself the appropriate number of times.

Step-by-step explanation: Please find the attached file for the solution

Ver imagen temdan2001

The use of

[tex] { {x}^{2} }^{k} [/tex]

is a more efficient way to multiplying than starting with x and successively squaring

Given:

real number = x

positive integer = k

[tex] { {x}^{2} }^{k} [/tex]

Starting with x and squaring to find x², x⁴, xⁿ

The efficient way of multiplying is

[tex] { {x}^{2} }^{k} [/tex]

where, k = 1, 2, 3, 4,.....…

check:

when k = 1

[tex] { {x}^{2} }^{1} [/tex]

= x²

when k = 2

[tex] { {x}^{2} }^{2} [/tex]

= x⁴

when k = 3

[tex] { {x}^{2} }^{3} [/tex]

=

[tex] { {x}^{2 \times 2 \times 2} } [/tex]

=

[tex] {x}^{8} [/tex]

Therefore,

[tex] { {x}^{2} }^{k} [/tex]

is a more efficient way to multiplying.

Learn more about exponent:

https://brainly.com/question/11464095