Answer:
12 units
Explanation:
This problem can be solved if we take into account the equation for a sphere
[tex]x^{2}+y^{2}+z^{2}=r^{2}\\x^{2}+y^{2}+z^{2}=(\frac{26}{2})^{2}=13^{2}[/tex]
where we took that the radius is 13 units. If we take z=5 and we replace this value in the equation of the sphere we have
[tex]x^{2}+y^{2}+(5)^{5}=13^{2}\\x^{2}+y^{2}=144=(12)^{2}[/tex]
where we have taken x2 +y2 because if the equation of a circunference.
In this case the intersection is made when we take z=5, for this value the sphere and the plane coincides in values.
Hence, the radius is 12 units
I hope this is useful for you
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