Answer:
E) bounded from both above and below.
Step-by-step explanation:
Sequences
The given sequence is
[tex]a_n=\{sin\ n\}[/tex]
To obtain the terms of the sequence, we give n values from the natural numbers set, i.e.
[tex]n=\{1,2,3,4...\}[/tex]
The sequence is expanded as
[tex]\{sin\ 1,\ sin\ 2,\ sin\ 3,\ sin\ 4,\ ...\}[/tex]
Now we must recall some of the properties of the sine function: it's periodic and bounded from a minimum value (-1) to a maximum value (1), that is
[tex]-1\leq sin \ n\leq 1[/tex]
Thus, the correct answer is
E) bounded from both above and below.
