Answer:
The answer is 2X as much illumination as connection in series
Explanation:
We are given from the question that the two bulbs are identical in power and resistance.
Firstly we know that In a series connection the Voltage across the circuit elements are different whereas In a parallel connection, the same value of voltage passes through all the circuit elements.
Power is expressed as ;
P = V^2/ R
An increase in voltage leads to an increase in power likewise if the voltage is reduced the power also reduces.
The two bulbs are said to be having the same resistances , so the voltage across them in a series connection will be halved
V =1/2V1 + 1/2 V2; making the illumination across them to be low.
Therefore in parallel the illumination will be twice as much the illumination when connected in series.
Answer:
E
Explanation:
When the two identical electric bulbs of power P and resistance are connected in series;
P = IV = V ( V/R) = V² / R
and V = IR
for series connection, the effective resistance Rf = R + R = 2R
and current in the circuit I₁ = V / 2R
for the parallel connection ,
[tex]\frac{1}{Rf}[/tex] = [tex]\frac{1}{R}[/tex] +
Rf = R / 2
I₂, in the circuit = 2 V / R
comparing the current,
I₂ ÷ I₁ = 2 V / R ÷ V / 2R = 4 : 1
The illumination is 4 times as greater in connection in series
