Answer:
1.
The relation is: f = Θ(g)
For c1 = 1 and c2 = 200, and n >= 0, we have
0 <= g(n) <= f(n) <= 200*g(n)
Hence, f = Θ(g)
2.
The relation is: f = Ω(g)
For very large values of n,
0 <= g(n) <= f(n)
Hence, f = Ω(g)
3.
The relation is: f = Ω(g)
Since, for n >= 0,
log2n > log3n
Hence, f = Ω(g)
4.
The relation is: f = Big-O(g)
For all n >= 0,
2n <= 3n
Hence, f = Big-O(g)
5.
The relation is: f = Big-O(g)
For n >= 0,
0.5n < 1
Hence, f = Big-O(g)
Explanation: