Answer:
[tex]P_{2} = 3.272\,atm[/tex]
Explanation:
Let consider that gas behaves ideally, the following relation is used:
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]
The final pressure is:
[tex]P_{2} = P_{1} \cdot \frac{T_{2}}{T_{1}}[/tex]
[tex]P_{2} = (3\,atm)\cdot \left(\frac{325.15\,K}{298.15\,K} \right)[/tex]
[tex]P_{2} = 3.272\,atm[/tex]