Respuesta :
Answer: 1×10^-5 N
Explanation: The force per unit length between both current carrying conductors is defined by the formulae below
F/L = u ×I1×I2/ 2πr
Where F = Force on both conductors,
L = length of both conductors = 1m,
I1 = I2 = 1A = current on both conductors,
r = 2m = distance separating conductors
u = permeability of free space = 1.256×10^-6 mkg/s²A²
By substituting the parameters, we have that
F/ 1 = (1.256×10^-6 ×1 ×1) / 2× 3.142 ×2
F/ 1 = 1.256×10^-6/ 12.566
F = 1.256×10^-6 / 12.566
F = 0.1×10^-6
F = 1×10^-5 N
Answer: F=1x10^-7N
Explanation:
Let the force on both conductors be F;
F=(U * I1 *I2 *k )/2[tex]\pi[/tex]d .........1
U=4[tex]\pi[/tex]X10^-7
I1=1.0A
I2=1.0A
k=1.0m
d=2.0m
Substituting , we have
F=(4[tex]\pi[/tex]X10^-7x1x1x1)/(2[tex]\pi[/tex]x2)
F=1x10^-7N
