Answer:
See Below
Step-by-step explanation:
The equation isn't properly given. Rather, I will do a similar problem available online. The question is:
The threshold weight T for a person is the weight above which the risk of death increases greatly. The threshold weight in pounds for men aged 40 - 49 is related to height h in inches by the formula
[tex]h=12.3\sqrt[3]{T}[/tex]
What height corresponds to a threshold weight of 216 Ib for a 43 -year-old man? Round your answer to the nearest inch and then to the nearest tenth of a foot.
Solution:
43 year old man falls into the the age group of 40-49 and thus the formula is shown above.
We want the height "h" corresponding to a weight of 216 pounds. So we plug in 216 into T of the formula and find our answer for h (in inches):
[tex]h=12.3\sqrt[3]{T}\\h=12.3\sqrt{3}{216}\\h=12.3*6\\h=73.8[/tex]
The height is 73.8 inches, nearest inch is 74 inches
74/12 = 6.16 feet, nearest feet is 6 ft
