Answer: 3.57N
Explanation:
given
Speed of rotation, N = 1300 rpm
diameter, d = 35 cm, so that
radius, r = 17.5 cm = 0.175 m
mass of drop = 1.1 g = 1.1*10^-3 kg
Angular speed of water, ω = 2πN/60
ω = 2π*1300/60
ω = 8169.2/60
ω = 136.15 rad/s
apparent weight will be gotten by
W(a) = mω²r
W(a) = 1.1*10^-3 * 136.15² * 0.175
W(a) = 1.1*10^-3 * 18536.82 * 0.175
W(a) = 3.57 N
Therefore, the apparent weight of 1.1 g of water is 3.57 N