Answer:
2.5 [tex]ms^-^2[/tex]
Explanation:
As we can see in the question that initial and final directions of the velocity of the object are same i.e. east, so it is clear that object is in a straight line motion.
Given that,
Initial velocity of the object = 3 m/s
Final velocity of the object = 8 m/s
Time interval = 2 seconds
The following equation of motion in straight line can be used -
[tex]v=u+at[/tex]
And thus acceleration can be calculated as
[tex]a=\frac{v-u}{t}[/tex] where, [tex]v[/tex] is final velocity and [tex]u[/tex] is initial velocity.
So, [tex]a= \frac{8-3}{2} = 2.5 ms^-^2[/tex]
The magnitude of the acceleration of the object is [tex]2.5 \;\rm m/s^{2}[/tex].
Given data:
The initial velocity of object is, u = 3.0 m/s.
The final velocity of object is, v = 8.0 m/s.
The time interval is, t = 2.0 s.
The given problem is based on the first kinematic equation of motion, which defines the acceleration of an object. According to first kinematic equation of motion,
v = u + at
Here, a is the magnitude of acceleration of the object.
Solving as,
8.0 = 3.0 + (a)2
a = (8.0 - 3.0 )/2
a = 5/2
[tex]a =2.5 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of the acceleration of the object is [tex]2.5 \;\rm m/s^{2}[/tex].
Learn more about the first kinematic equation of motion here:
https://brainly.com/question/14355103
