Answer:
Explanation:
Hello,
For the given reaction:
[tex]2A(g)\rightleftharpoons B(g) ; Kp=9.58x10^{-5}[/tex]
In such a way, the law of mass action, in terms of the pressures of both A and B at equilibrium result:
[tex]Kp=\frac{p_B}{p_A^2}[/tex]
Thus, by introducing the change [tex]x[/tex], due to equilibrium, we obtain:
[tex]Kp=\frac{x}{(p_A_0-2x)^2}[/tex]
Hence, solving for [tex]x[/tex] by solver or quadratic equation, we get:
[tex]x=1.24x10^{-3}atm[/tex]
Finally, since the pressure of B at equilibrium equals the change, it results:
[tex]p_B^{eq}=1.24x10^{-3}atm[/tex]
Best regards.
