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What volume (in mL) will a sample of F2 gas occupy in a syringe at 5.5 atm, if the F2 has a volume of 25.0 mL at 1.2 atm?



Group of answer choices

11 mL

17 mL

3.8 mL

5.5 mL

7.6 mL

Respuesta :

Answer:

The correct answer is 5,5 ml

Explanation:

We use the Boyle´s Mariotte formula (for a given mass of gas, at constant temperature, the pressure and volume vary inversely proportionally):

P1xV2=P2XV2 --> V2=(P1xV2)/P2

V2=(1,2atm x 25,0 ml)/5,5 atm=5,45 ml

onyebuchinnaji

The volume of the gas at the initial pressure of 5.5 atm is 5.5 mL.

The given parameters:

  • initial pressure of the gas, P₁ = 5.5 atm
  • final pressure of the gas, P₂ = 1.2 atm
  • final volume of the gas, V₂ = 25 mL

The initial volume of the of the gas is calculated by applying Boyles Law;

[tex]P_1V_1 = P_2V_2\\\\V_1 = \frac{P_2V_2}{P_1} \\\\V_1 = \frac{1.2 \times 25}{5.5} \\\\V_1 = 5.5 \ mL[/tex]

Thus, the volume of the gas at the initial pressure of 5.5 atm is 5.5 mL.

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