The cost function for q units of a certain item is ​C(q)equals109 q plus 90. The revenue function for the same item is ​R(q)equals109 q plus StartFraction 45 q Over ln q EndFraction . a. Find the marginal cost. b. Find the profit function. c. Find the profit from one more unit sold when 8 units are sold.

Respuesta :

Answer:

a) $109

b) [tex]P(q) = \frac{45q}{ln(q)} +90[/tex]

c) [tex]$11.20[/tex]

Step-by-step explanation:

a) The marginal cost, or the cost per additional unit, is given by the derivate of the cost function:

[tex]C(q) = 109q+90\\C(q) = \$109[/tex]

b) Profit is given by Revenue minus Cost:

[tex]P(q) = R(q) - C(q)\\P(q) = \frac{45q}{ln(q)} +90[/tex]

c) The marginal profit for 8 units, is given by the difference in profit for 9 units and 8 units:

[tex]M = P(9)-P(8)\\M= \frac{45*9}{ln(q)} +90 - (\frac{45*8}{ln(8)}+90 )\\M=\$11.20[/tex]

By applying the basic formulae,

a) $109

b)[tex]P(q) = \frac{45q}{lnq} - 90[/tex]

c) $11.20

What is the relation between marginal cost and cost function?

Marginal cost is a derivative of the Cost function.

a)Marginal cost

C(q) = 109q + 90

[tex]M(q) = \frac{d}{dq} C(Q)=\frac{d}{dq} ( 109q+90)\\\\M(q) = 109$[/tex]

Marginal cost = $109

(b)Profit function P(q) = Revenue function R(q) - Cost function C(q)

[tex]P(q) = (109q + \frac{45q}{ln q}) - (109q +90) = \frac{45q}{lnq} -90[/tex]

(c) Marginal profit = P(9)-P(8)

Marginal profit [tex]= \frac{45*9}{ln9} - \frac{45*8}{ln8}= 11.20[/tex]

Thus we find Marginal cost, Profit function, and Marginal profit as,

a) $109

b) [tex]P(q) = \frac{45q}{lnq} - 90[/tex]

c) $11.20

To get more about cost function, revenue function, profit function, etc. refer to the link,

https://brainly.com/question/2292799