Answer:
2.475 mol of O2 formed.
Explanation:
Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.
x mole of O2 = 1.65 mol KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2
x mole of O2 formed = 2.475 mol of O2
The number of mole of O₂ that will be formed from 1.65 moles of KClO₃ is 2.475 moles
The balanced equation is given below
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂
Therefore,
1.65 moles of KClO₃ will decompose to produce = (1.65 × 3)/2 = 2.475 moles of O₂
Thus, 2.475 moles of O₂ were obtained from the reaction.
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