Respuesta :
Answer:
Acceleration of Sea Lion is 4.41 g
This is 49% of maximum jet acceleration given as a = 9g
Explanation:
As we know that the radius of the circular loop is given as
R = 0.37 m
The speed of the fish is given as
[tex]v = 4 m/s[/tex]
Now the centripetal acceleration of the sea lion is given as
[tex]a_c = \frac{v^2}{R}[/tex]
[tex]a_c = \frac{4^2}{0.37}[/tex]
[tex]a_c = 43.2 m/s^2[/tex]
as we know that
[tex]g = 9.8 m/s^2[/tex]
so we have
[tex]a = 4.41 g[/tex]
Now Percentage of this acceleration wrt maximum jet acceleration is given as
[tex]P = \frac{4.41 g}{9g} \times 100[/tex]
[tex]P = 49 [/tex]%
The value of centripetal acceleration is 4.41g.
The centripetal acceleration is 49% of the maximum acceleration F-15 fighter plane.
Given data:
The radius of circular turn is, r = 0.37 m.
The speed lion during the turn is, v = 4.0 m/s.
The centripetal acceleration is the center seeking acceleration produced by the force acting on the body during motion in a circular path. And standard expression for the centripetal acceleration is,
[tex]a =\dfrac{v^{2}}{r} \\\\a =\dfrac{4^{2}}{0.37}\\\\a = 43.24 \;\rm m/s^{2}[/tex]
We known that the value of g is [tex]9.8 \;\rm m/s^{2}[/tex]. So divide and multiply a with g as,
[tex]a =\dfrac{43.24 \;\rm m/s^{2} \times g}{g} \\\\ a =\dfrac{43.24 \;\rm m/s^{2} \times g}{9.8 \;\rm m/s^{2}} \\\\a = 4.41g[/tex]
Thus, we can conclude that the value of centripetal acceleration is 4.41g.
And the percentage is this acceleration of that of an F-15 fighter jet's maximum centripetal acceleration of 9g is,
[tex]=\dfrac{a}{9g} \times 100\\\\ =\dfrac{4.41g}{9g} \times 100\\\\=49\%[/tex]
Thus, we can conclude that the centripetal acceleration is 49% of the maximum acceleration F-15 fighter plane.
Learn more about the centripetal acceleration here:
https://brainly.com/question/14465119
