Respuesta :
Answer:
Cl₂O₇
Explanation:
For the reaction:
ClₓOₙ + H₂ → HCl + H₂O
Moles of HCl and moles of H₂O are:
HCl: 0.233g HCl ₓ (1mol / 36.46g) = 6.39x10⁻³ mol HCl
H₂O: 0.403g H₂O ₓ (1mol / 18.02g) = 2.236x10⁻² mol H₂O
As you can see, moles of HCl are equivalent to moles of Cl in the compound and moles of H₂O are equivalent to moles of O in the compound, that means:
6.39x10⁻³ mol Cl
2.236x10⁻² mol O
Empirical formula is the simplest ratio of atoms presents in a molecule. If Cl is 1, Oxygen will be:
2.236x10⁻² mol / 6.39x10⁻³ = 3.5
As empirical formula must be given in natural numbers, the empirical formula is:
Cl₂O₇
Answer:
Cl2O7
Explanation:
Molar mass of HCl= 36.5gmol-1
Molar mass of water =18gmol-1
To get the ratio of chlorine present in the original substance
0.233/36.5= 0.00638
To get ratio of oxygen present in the original compound
0.403/18= 0.0224
Then divide through by the lowest ratio
Cl- 0.00638/0.00638 O- 0.0224/0.00638
Cl- 1 O- 3.5
Multiplying through by 2 to give whole numbers
Cl-2. O-7
Hence the empirical formula of the compound is Cl2O7