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A rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black, and 8 are white. What is the simplest explanation for the inheritance of these colors in chickens? What offspring would you predict from the mating of a gray rooster and a black hen?

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Oseni

Answer:

Alleles for feather colour exhibit incomplete dominance or co-dominance.

50% gray offspring + 50% black offspring

Explanation:

It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.

Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.

Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.

15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.

Bb   x   Bb = 1BB, 2Bb, and 1bb

Crossing the gray rooster (Bb) with a black hen (bb):

Bb   x   bb = Bb, Bb, bb, and bb

          = 2Bb (gray):2bb (black)

50% of the offspring will be gray while the remaining 50% will be black.

Incomplete dominance occurs when the mating of two different phenotypes gives rise to a third phenotype.

The simplest explanation for this inheritance would be incomplete dominance. The offspring produced from a cross of gray and black would be gray and there would be black too.

A rooster with gray feathers is mated with a gray hen

  • The gray colour is the incomplete phenotype (Tt)
  • The black phenotype would be the dominant phenotype (TT) and the white the (tt).

Cross between gray  and gray  produces

     Tt    x     Tt

   TT   Tt   Tt     tt

      1    :    2    :   1

     6   :    15  :  8 (from the mating)

A cross between a gray rooster and a black hen would give:

Parent        Tt      x    TT

Offspring   TT          Tt

                    1      :     1

Learn more about incomplete dominance: https://brainly.com/question/13612556

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