A monochromatic beam of light has a frequency

of 7.69 × 10^14 hertz. What is the energy of a

photon of this light?

(1) 2.59 × 10^−40 J (3) 5.10 × 10^−19 J

(2) 6.92 × 10^−31 J (4) 3.90 × 10^−7 J

Respuesta :

Answer:

(3) 5.10x[tex]10^{-19} J[/tex]

Explanation:

If you already know the frequency, the energy of photon can be calculated by using the formula :

E=hf

where,

E= energy of photon

f= frequency of the photon in Hz=  7.69 × 10^14 hertz

h=Planck's constant = 6.63 × 10-34 J s

therefore, E= (6.63 × 10^-34 )*(7.69 × 10^14 )

E= 5.09x10^-19 J ≈ 5.10× 10^−19 J

∴The energy of a  photon of this light is 5.10× 10^−19 J

The energy of a  photon of this light is 5.10×  10⁻¹⁹J.

What is the frequency?

Frequency is the number of oscillations per second in the sinusoidal wave.

If f is the frequency, then energy of photon can be represented as

E=hf

where, E= energy of photon, f= frequency in Hz=  7.69 × 10¹⁴ Hz and h is Planck's constant = 6.63 × 10⁻³⁴ J s.

Substituting the values, we get the energy of photon

E= (6.63 ×  10⁻³⁴ )*(7.69 × 10¹⁴)

E= 5.10× 10⁻¹⁹ J

Therefore, the energy of a  photon of this light is 5.10×  10⁻¹⁹J.

Learn more about frequency.

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