Answer: a) electric field will be zero at zero meters apart
b) for smaller charge q, E = 6.048X10^6N/m towards away from the charge,
for bigger charge Q, E = 4.032X10^6N/m
Explanation:
Detailed explanation and calculation is shown in the image below.
The electric field strength is directly proportional to the force exerted on chareges. The electric field will be zero only at the point charges not in between them.
[tex]E = \dfrac F Q[/tex]
Where,
[tex]E [/tex] - electric field strength
[tex]F [/tex] - force = [tex]\dfrac {1}{4\pi}\times \dfrac {Qq}{r^2}[/tex]
[tex]Q[/tex] - charge
So, for the smaller charge,
[tex]E = \dfrac {1}{4\pi\epsilon_0}\times \dfrac {Q}{r^2}[/tex]
Where,
[tex]r[/tex] - distance
For E to be zero,
[tex]0= \dfrac {1}{4\pi\epsilon_0}\times \dfrac {Q}{r^2}\\\\ 0 = \dfrac {r^2}Q\\\\ r = 0[/tex]
Therefore, the electric field will be zero only at the point charges not in between them.
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