Answer:
(2,7)
Step-by-step explanation:
5x+3y=31
2x+3y=25
Multiply the second equation by -1
-2x -3y = -25
Add this to the first equation
5x+3y=31
-2x-3y=-25
--------------------
3x = 6
Divide each side by 3
3x/3 = 6/3
x =2
Now we need to solve for y
5x+3y = 31
5*2 +3y = 31
10+3y = 31
Subtract 10 from each side
10-10 +3y = 31-10
3y = 21
Divide by 3
3y/3 = 21/3
y= 7
Answer:
x = 2
y = 7
Step-by-step explanation:
in order to solve this system of equation using elimination method we say let
5x+3y=31............................................ equation 1
2x+3y=25........................................... equation 2
step 1
you are going to add -1 to equation 2 so u can have a negative sign
2x+3y=25........................................... equation 2
-1 (2x) + -1(3y) = -1(25)
after multiplying we have
-2x - 3y = -25..................................................... equation 3
Step 2
add equation 1 and equation 3 together
5x+3y=31............................................ equation 1
+
-2x - 3y = -25..................................................... equation 3
we have,
3x = 6
divide both sides by the coefficient of x which is 3
we have ,
3x/3 = 6/3
x = 2
put the value of x = 2 in equation 2
2x+3y=25........................................... equation 2
2(2) + 3y = 25
4 + 3y = 25
collect the like terms
3y = 25 - 4
3y = 21
divide both sides by 3
3y/3 = 21/3
y = 7
therefore the value of x = 2 and value of y = 7 respectively.
