Answer:
A
Step-by-step explanation:
We are given that a function
[tex]f(x)=x^2+8x+6[/tex]
We have to find the next step in the process and what is the extreme value .
By adding and subtracting 16 then we get
[tex]f(x)=(x^2+8x+16)+6-16[/tex]
[tex]f(x)=(x+4)^2-10[/tex]
By using the formula
[tex](a+b)^2=a^2+b^2+2ab[/tex]
The given function is the equation of parabola .
By comparing with
[tex]y=(x-h)^2+k[/tex]
Where vertex=(h,k)
Vertex=(h,k)=(-4,-10)
Substitute x=-4
Then, we get
[tex]f(x)=-10[/tex]
Hence, the extreme minimum value of function =-10
Option A is true.