The surface area of the triangular prism is 144 cm²
Explanation:
Given:
Base of the triangle = 4
Height of the triangle = 3
Hypotenuse of the triangle = 5
Length of the prism = 11
Surface area of the rectangular prism = ?
Surface area, A = [tex]ah + bh + ch + \frac{1}{2} \sqrt{-a^4+2(ab)^2 + 2(ac)^2-b^4 + 2(bc)^2 - c^4}[/tex]
On substituting the value, we get:
[tex]A = 4 X 11 + 3 X 11 + 5 X 11+\frac{1}{2} \sqrt{-(4)^4 + 2(4X3)^2+2(4X5)^2-3^4 + 2(3X5)^2 - 5^4} \\\\A = 144 cm^2[/tex]
Therefore, the surface area of the triangular prism is 144 cm²
