The length of AE is 22.36 cm
Step-by-step explanation:
Given,
In the fig: AB = 20 cm
E is the mid point of BC.
So, BE = 10 cm
To find the length of AD
Here,
ΔABE is a right angle triangle.
So,
[tex]AB^{2} +BE^{2} =AE^{2}[/tex]
Now, putting the values of AB and BE we get,
[tex]20^{2} +10^{2} =AE^{2}[/tex]
or, [tex]AE^{2}[/tex] = 400+100
or, AE = [tex]\sqrt{500}[/tex] = 10[tex]\sqrt{5}[/tex]
= 10×2.236 = 22.36 (approx)
