Answer:
69.3m
Step-by-step explanation:
-Given the base side length is 62m and the vertical height is 62m.
-The vertical height touches the square base at its midpoint. We therefore use half the base length and the height to calculate the slant heights.
#Using Pythagorean theorem:
[tex]b^2+h^2=H^2, h=62, b=0.5\times 62=31\\\\H^2=62^2+31^2\\\\H=4805^{\frac{1}{2}}\\\\=69.32\approx69.3 \ m[/tex]
Hence, the heights of the triangular faces is 69.3m
