For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 30 N acts on a certain object, the acceleration of the object is 5 m/s^2 . If the force is changed to 48 N , what will be the acceleration of the object?

Respuesta :

Answer:

The value of acceleration when force is changed to 48 N is = [tex]a_{2}[/tex]  = 8 [tex]\frac{m}{s^{2} }[/tex]

Step-by-step explanation:

Force [tex]F_{1}[/tex] = 30 N

Acceleration [tex]a_{1}[/tex] = 5 [tex]\frac{m}{s^{2} }[/tex]

Force [tex]F_{2}[/tex] = 48 N

Now Acceleration [tex]a_{2}[/tex] = ??

Given that the force acting on the object varies directly with the object's acceleration.

⇒ F ∝ a

⇒ [tex]\frac{F_{1} }{a_{1} } = \frac{F_{2} }{a_{2} }[/tex]

Put all the values in above formula we get

⇒ [tex]\frac{30}{5} = \frac{48}{a_{2} }[/tex]

[tex]a_{2}[/tex]  = 8 [tex]\frac{m}{s^{2} }[/tex]

This is the value of acceleration when force is changed to 48 N.