Respuesta :
Answer:
(1) 0.333 Hz
(2) 4 sec
(3) 2 sec, 0.5 Hz
Explanation:
(1) We have given time period of pendulum is 3 sec
So T = 3 sec
Frequency will be equal to [tex]f=\frac{1}{T}=\frac{1}{3}=0.333Hz[/tex]
(2) Frequency of the pendulum is given f = 0.25 Hz
Time period is equal to [tex]T=\frac{1}{f}=\frac{1}{0.25}=4sec[/tex]
(3) It is given that a pendulum makes 10 back and forth swings in 20 seconds
So time taken to complete 1 back and forth swings = [tex]=\frac{20}{10}=2sec[/tex]
So time period T = 2 sec
Frequency will be equal to [tex]f=\frac{1}{T}=\frac{1}{2}=0.5Hz[/tex]
Answer:
(1) 0.33 Hz
(2) 4 s
(3) 2 s, 0.5 Hz
Explanation:
The relation between frequency and time period is given as
[tex]f=\frac{1}{T}[/tex]
(1) Given a pendulum has a period, T = 3 s.
So, [tex]f=\frac{1}{3s}[/tex]
f = 0.333 Hz.
Thus, frequency of pendulum is 0.33 Hz.
(2) Given a pendulum has a frequency, f = 0.25 Hz.
So, [tex]T=\frac{1}{0.25 Hz}[/tex]
T = 4 s.
Thus , period of pendulum is 4 s.
(3) Frequency is measured in cycles/second.
Given a pendulum makes 10 back and forth swings in 20 seconds.
So,[tex]f=\frac{10 cycles}{20s}[/tex]
f = 0.5 Hz
Time period,
[tex]T=\frac{1}{0.5}[/tex]
T = 2 s.
Thus, period and frequency of pendulum are 2 s and 0. 5 Hz respectively.
