Answer:
38.89% probability that a student that is taking Physics is also taking Statistics
Step-by-step explanation:
Conditional probability formula:
Two events, A and B.
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of B happening, given that A has happened.
[tex]P(A \cap B)[/tex] is the probability of these two events happening.
P(A) is the probability of A happening.
In this problem, we have that:
A: physics
B: statistics.
90% of the students take Physics
This means that [tex]P(A) = 0.9[/tex]
35% of the students take both Physics and Statistics.
This means that [tex]P(A \cap B) = 0.35[/tex]
So
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.35}{0.90} = 0.3889[/tex]
38.89% probability that a student that is taking Physics is also taking Statistics
