Answer:
[tex]chang in V=\int\limits^B_A {E} \, ds[/tex]
Explanation:
Since, as we know, the potential difference 'ΔV' is the difference of between the Potential energy per unit charge U/qo at one point 'B' to Potential energy per unit charge at other point 'A'. It so happens when a test charge 'qo' moves from point A to B, the potential difference becomes the change of potential energy of the system, i.e.
[tex]Potential Difference =\frac{change in U}{qo}=\int\limits^B_A {E} \, ds[/tex]
