Respuesta :
Answer:
Electric field will be equal to 1000 N/C
Explanation:
We have given charge [tex]q=5mC=5\times 10^{-3}C[/tex]
It is given that this charge is in influence of 5N
So electrostatic force F = 5 N
We have to find the electric field
Force on any charge in an electric field is equal to [tex]F=qE[/tex]
So [tex]5=5\times 10^{-3}\times E[/tex]
E = 1000 N/C
So electric field/ will be equal to 1000 N/C
Answer:
1000 N/C
Explanation:
The relation between electric field, electric force and charge is given as
[tex]E=\frac{F}{q}[/tex]
Here E is electric field, F is the electric force and q is the electric charge.
The magnitude of electric field,
[tex]|E|=\frac{|F|}{q}[/tex]
Given F = 5.0 N and q =5 mC.
Substitute the given values, we get
[tex]|E|=\frac{5N}{5\times 10^-^3C}[/tex]
|E| = 1000 N/C
Thus , the magnitude of the electric field is 1000 N/C.
