An electron is located in an electric field of magnitude 600 Newton's per coulomb. What is the magnitude of the electrostatic force acting in the electron?

Respuesta :

Answer:  

force on electron will be equal to [tex]9.6\times 10^{-17}N[/tex]

Explanation:

We have given magnitude of electric field E = 600 N/C

Charge on electron [tex]e=1.6\times 10^{-19}C[/tex]

We have to find the electric force on the electron

Force in electric field is equal to [tex]F=qE[/tex], here q is charge and E is electric field

So force will be equal to [tex]F=1.6\times 10^{-19}\times 600=960\times 10^{-19}=9.6\times 10^{-17}N[/tex]

So force on electron will be equal to [tex]9.6\times 10^{-17}N[/tex]

Answer:

The magnitude of the electrostatic force acting in the electron is [tex]9.6\times 10^-^1^7N[/tex].

Explanation:

The relation between electric field, electric force and charge is given as

[tex]F=eE[/tex]

Here E is electric field, F is the electric force and e is the electric charge on electron.

Given [tex]F=600N/C,\ e=-1.6\times10^-^1^9C[/tex].

Substitute the given values, we get

[tex]F=-1.6\times10^-^1^9C\times600N/C[/tex]

The magnitude of force,

[tex]|F|=9.6\times10^-^1^7N[/tex].

Thus, the magnitude of the electrostatic force acting in the electron is [tex]9.6\times 10^-^1^7N[/tex].