The function P(t) gives the number of insects in a population at time t. The birth rate for the insects is 6.7 % per unit of time and the death rate is 2 % per unit of time. Give the rate of change of the population with respect to time in terms of P.

Respuesta :

Answer:

dP/dt = 0.047P

Step-by-step explanation:

- Let P(t) be the number of insects at time t.

- Let the birth rate for the insects be b(t, P) , then b(t, P) = 6.7% = 0.067

- Let the death rate for the insects be d(t, P) , the d(t, P) = 2% = 0.02

The number of insects between time t and t + Δt is given as

Total birth = bPΔt

Total death = dPΔt

The rate of change of population with respect to time is

ΔP = bPΔt - dPΔt

ΔP = (b - d)PΔt

ΔP/Δt = (b - d)P

Taking the limit as ΔP approaches 0

dP/dt = (b - d)P

Using the values of b and d, we have

dP/dt = (0.067 - 0.02)P = 0.047

dP/dt = 0.047P

The rate of change should be dP/dt = 0.047P

Calculation of the rate of change:

Since we assuming the following things:

P(t) be the number of insects at time t.

The birth rate for the insects be b(t, P) , so b(t, P) = 6.7% = 0.067

And, the death rate for the insects be d(t, P) , the d(t, P) = 2% = 0.02

Now

The number of insects between time t and t + Δt should be provided

Total birth = bPΔt

Total death = dPΔt

Now The rate of change should be

ΔP = bPΔt - dPΔt

ΔP = (b - d)PΔt

ΔP/Δt = (b - d)P

Now we considered the limit as ΔP approaches 0

So,

dP/dt = (b - d)P

Now

dP/dt = (0.067 - 0.02)P = 0.047

dP/dt = 0.047P

hence, The rate of change should be dP/dt = 0.047P

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