Answer:
The answers are;
1. 8.2 liters
2. 1214.84 ml
3. 318.027 K
4. 4.00 l.
Explanation:
1. Boyle's law states that the volume of given mass of gas is inversely proportional to its pressure at constant temperature
that is
P₁·V₁ = P₂·V₂
Where:
P₁ = Initial pressure = 40.0 mm Hg
V₁ = Initial volume = 12.3 liters
P₂ = Final pressure = 60.0 mm Hg
V₂ = Final volume = Required
From P₁·V₁ = P₂·V₂, V₂ is given by
[tex]V_2=\frac{P_1\cdot V_1}{P_2} = \frac{40.0 mm Hg\cdot 12.3 l}{60.0 mm Hg}[/tex] = 8.2 l
The volume reduces to V₂ = 8.2 liters
2. Here Charles law states that
[tex]\frac{T_1}{V_1} =\frac{T_2}{V_2}[/tex]
T₁ = Initial temperature = 27.0 °C = 300.15 K
V₁ = Initial volume = 900.0 mL
T₂ = Final temperature = 132.0 °C = 405.15 K
V₂ = Final volume = Required
Therefore [tex]V_2 =\frac{T_2\cdot V_1}{T_1}[/tex] = [tex]\frac{405.15 K\times 900.0 mL}{300.15 K}[/tex] = 1214.84 ml
V₂ = 1214.84 ml
3. Gay-Lussac's Law states that
[tex]\frac{T_1}{P_1} =\frac{T_2}{P_2}[/tex]
Where:
P₁ = Initial pressure = 15.0 atmospheres
T₁ = Initial temperature = 25.0 °C = 298.15 K
P₂ = Final pressure = 16.0 atmospheres
T₂ = Final temperature = Required
∴ [tex]T_2 = \frac{T_1\times P_2}{P_1}[/tex]
= [tex]\frac{298.15 K\times 16.0atm}{15.0atm}[/tex] = 318.027 K
T₂ = 318.027 K
4. Avogadro's law states that,
Equal volume of all gases at the same temperature and pressure contain equal number of molecules.
Therefore if 5.00 moles of gas occupies 2.00 l volume, then
1 moles will occupy 2.00/5 l volume and
10 moles will occupy 2.00/5 × 10 or 4.00 l volume.