A bullet has a mass of 0.0042kg. The muzzle velocity of the bullet coming out of the barrel of the rifle is 993m/s. What is the KE of the bullet as it exits the gun barrel?

Respuesta :

Answer: 2070.7029J

Explanation: the bullets travels with a kinetic energy

K.E=½MV²

K.E=½×0.0042×993²

K.E=0.0021×986049

K.E=2070.7029J

Answer:

Explanation: the bullets travels with a kinetic energy

K.E=½MV²

K.E=½×0.0042×993²

K.E=0.0021×986049

K.E=2070.7029J

Explanation: