Answer:
2F
Explanation:
Given;
[tex]F=\frac{Gm_1m_2}{r^2}................(1)[/tex]
G is is the universal gravitational constant. Since G is a constant, we could rewrite equation (1) as follows;
[tex]\frac{Fr^2}{m_1m_2}=constant (G)................(2)[/tex]
When one of the masses is altered, the force changes to a new value, say [tex]F_2[/tex].
In this case it is said that [tex]m_1[/tex] is doubled.
Equation (2) therefore implies that we can write the following;
[tex]\frac{Fr^2}{m_1m_2}=\frac{F_2r^2}{2m_1m_2}...........(3)[/tex]
We are assuming that all other parameters a parts from [tex]m_1[/tex] remain the same.
By appropriately cancelling out parameters from both side of the equation (3), we obtain the following;
[tex]F=\frac{F_2}{2}[/tex]
The new gravitational force in terms of F is therefore'
[tex]F_2=2F[/tex]
