contestada

Two workers are sliding 310 kg crate across the floor. One worker pushes forward on the crate with a force of 380 N while the other pulls in the same direction with a force of 270 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?

Respuesta :

fahadisahadam

Answer:

[tex]0.214[/tex]

Explanation:

The sketch is in the attachment.

since its speed is constant, the acceleration is zero .

The total force will be:

[tex]F=380N+270N\\F=650N[/tex]

mass of the block is: [tex]m=310kg[/tex]

so now we can apply the formula to find the crate's coefficient of kinetic friction.

[tex]F=u_{k} mg\\u_{k} =\frac{F}{mg} \\u_{k}=\frac{650}{310*9.81} \\u_{k} =0.214[/tex]

Ver imagen fahadisahadam

Otras preguntas