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The null and alternative hypotheses for a population proportion, as well as the sample results, are given. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: H0:p=0.6 vs Ha:p> 0.6; Sample data: p^=5280=0.65 with n=80 Round the p-value to three decimal places.

Respuesta :

Considering the test statistic, the p-value is of 0.

What is the test statistic?

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

  • [tex]\overline{p}[/tex] is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are:

[tex]n = 5280, \overline{p} = 0.65, p = 0.6[/tex].

Hence:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.65 - 0.6}{\sqrt{\frac{0.6(0.4)}{5280}}}[/tex]

[tex]z = 7.42[/tex]

Considering a right-tailed test with z = 7.42, the p-value is of 0.

More can be learned about the p-value of a test at https://brainly.com/question/26454209

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