Respuesta :
Answer:
a = 2d / t²
or
a = 2gh / (3d)
Explanation:
One method is to use the equation:
Δx = v₀ t + ½ at²
d = (0) t + ½ at²
d = ½ at²
a = 2d / t²
By measuring the length of the incline d, and the time it takes to reach the bottom t, the students can calculate the acceleration, using only the meter stick and the stopwatch.
Another method is to use conservation of energy to find the final velocity.
Initial potential energy = final rotational energy + kinetic energy
PE = RE + KE
mgh = ½ Iω² + ½ mv²
For a solid cylinder, I = ½ mr². For rolling without slipping, ω = v/r.
mgh = ½ (½ mr²) (v/r)² + ½ mv²
mgh = ¼ mv² + ½ mv²
mgh = ¾ mv²
4gh/3 = v²
Using constant acceleration equation:
v² = v₀² + 2aΔx
4gh/3 = 0² + 2ad
a = 2gh / (3d)
Using this equation, the students can measure the height of the incline h, and the length of the incline d, to calculate the acceleration. The only equipment needed is the meter stick.
When carrying out experiment to find the acceleration, it is important that the experiment should be repeated several times when using the stopwatch
The acceleration of the cylindrical object down the plane can be measured using the meterstick , the stopwatch and the following equation with several repeated measurements;
[tex]Acceleration, \ a= \mathbf{\dfrac{2 \cdot d}{t^2}}[/tex]
With the use of only the meterstick, the height, h, and length, d, of the ramp can be measured, from which the acceleration can be found with the equation;
[tex]Acceleration, \ a \approx \mathbf{\dfrac{9.81 \times h}{3 \cdot d}}[/tex]
The reason the above equations can be used to find the acceleration of the cylinder are as follows:
The available equipment are;
- A stop watch with time intervals up to 999 seconds and a precision of 0.01 seconds
- A 12 hour clock with 1 minute precision
- A meterstick that can measure up to a meter with 1 mm precision
- A pair of calipers with capacity to measure up to 10 cm and having a precision of 0.05 mm
The equations of constant acceleration are;
1) [tex]d = v_0 \times t + \dfrac{a \times t^2}{2}[/tex]
2) [tex]v^2 = v_0^2 +2\cdot a \cdot d[/tex]
3) [tex]d = \dfrac{v^2 - v_0^2}{2 \cdot a}[/tex]
From the first equation, the initial velocity is zero, therefore, the acceleration becomes;
[tex]a= \dfrac{2 \cdot d}{t^2}[/tex]
Where:
d = The length of the ramp, measured with the meter rule
t = The time it takes the cylinder to reach the bottom of the ramp, measured with the stopwatch
From equation (2), the acceleration is given as follows;
v² = 2·a·d
[tex]a = \dfrac{v^2}{2 \cdot d} = \dfrac{\left(\dfrac{2\times d}{t} \right)^2}{2 \cdot d} = \mathbf{\dfrac{2 \cdot d}{t^2}}[/tex]
Which can be measured using the stopwatch and the meter rule
Energy conservation method
Using the energy conservation principle, gives;
Potential energy = Total kinetic energy
Potential energy = m·g·h
Total kinetic energy = Translational inertia + Rotational inertia
Total kinetic energy = [tex]\mathbf{ \left(\dfrac{1}{2} \cdot m \cdot v^2 \right) + \left(\dfrac{1}{2} \cdot I \cdot \omega^2 \right)}[/tex]
For the solid cylinder, we get;
[tex]Total \ kinetic \ energy = \left(\dfrac{1}{2} \cdot m \cdot v^2 \right) + \left(\dfrac{1}{2} \cdot \dfrac{1}{2} \cdot m \cdot r^2 \cdot \dfrac{v^2}{r^2} \right) = \dfrac{3}{4} \cdot m \cdot v^2[/tex]
Therefore;
[tex]m \times g \times h = \dfrac{3}{4} \cdot m \cdot v^2[/tex]
[tex]g \times h = \dfrac{3}{2} \cdot a \cdot d[/tex]
[tex]The \ acceleration, \ a = \dfrac{g \times h}{3 \cdot d} \approx \mathbf{ \dfrac{9.81 \times h}{3 \cdot d}}[/tex]
Therefore, the height, h and the length of the ramp, d, can be measured with the meter rule, from which the acceleration can be determined
Learn more about experiments to determine acceleration here:
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