Answer:
F1=40.9 N
F2=65.4 N
Explanation:
the diagram is shown in the picture. The torque of forces in A=0
[tex]-F_{1} DA-2.5gBA+F_{2}CA=0\\ -4.9F_{1} +4F_{2} =2.5*9.8\\ -4.9F_{1} +4F_{2} =61.25[/tex]
Along vertical is:
[tex]F_{1} -F_{2} +2.5g=0\\F_{1} -F_{2}=-24.5[/tex]
solving F1 in the first equation and replacing that value in the second equation we can calculate the values of F1 and F2:
F1=40.9 N
F2=65.4 N