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Suppose two point charges, Q1 = +3.37 x 10^-6 C and Q2 = -8.21 x 10^-6 C, are separated by a distance d = 1.99 m.

Using Coulomb's Law, find the attractive force between the charges.


A)
F = 0.0626 N


B)
F = 0.0313 N

C)
F = -0.0626 N

D)
F = -0.0313 N

Respuesta :

Tsarina
Option (C) is the correct one.



Explanation:
Coulmbs law here is,

[tex] \frac{9 \times {10}^{9} \times ( - 8.21 \times {10}^{ - 6} )(3.37 \times {10}^{ - 6} )}{ {(1.99)}^{2} } \\ \\ = - 0.0628 \\ [/tex]

Which is almost equal to optionC.

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